Question

Find the value of k if eq kx2+2x+1 has equal

Answer 1

Answer:

For equal roots,

D=b2-4ac=0     (b square-4ac)

D=4-4k=0

=> 4=4k

=> k=1

Answer 2

for equal roots the determinant shuld be equal to 0
so
a=k
b=2
c=1
(under square root)b2-4ac
=2^2-4×k×1=0
4-4k=0
-4k=0+4
-4k=4
k=-4/4
k=-1