Find the value of k if eq kx2+2x+1 has equal
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0
Answer:
For equal roots,
D=b2-4ac=0 (b square-4ac)
D=4-4k=0
=> 4=4k
=> k=1
aarnav202:
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Answered by
1
for equal roots the determinant shuld be equal to 0
so
a=k
b=2
c=1
(under square root)b2-4ac
=2^2-4×k×1=0
4-4k=0
-4k=0+4
-4k=4
k=-4/4
k=-1
so
a=k
b=2
c=1
(under square root)b2-4ac
=2^2-4×k×1=0
4-4k=0
-4k=0+4
-4k=4
k=-4/4
k=-1
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