Question

Find the value of 'k' if on dividing 2x^3 + 3x^2 - kx + 5 by (x - 2) leaves a remainder 7.

Answer 1

Answer:

Let f(x)=2x

3

+3x

2

−kx+5

By remainder theorem, when f(x) is divided by (x−2)

x−2=0,⇒x=2

the remainder =f(2)

=2(2)

3

+3(2)

2

−k(2)+5

=16+12−2k+5

=33−2k

According to question

33−2k=7

⇒2k=26

k= 13

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