Find the value of k if on division of 2x^3-3x^2-7x+k by x-2, the remainder is 2.
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As divisor is x-2, u hv to put 2 in the polynomial
2*2^3-3*2^2-7*2+k=2
16-12-14+k=2
K=2+10=12
2*2^3-3*2^2-7*2+k=2
16-12-14+k=2
K=2+10=12
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