Question

find the value of k if Q.E have two equal and real roots k²x²-2(2k-1)x+4=0. 2) (k+1)x²-2(3k+1)x+(8k+1)=0​

Answer 1

Step-by-step explanation:

k2x2-2(k-1)x+4=0 - Brainly.i

∵ The roots of given equation are real and equal. ∴ ∆ must be zero. ∴ – 12k2 – 8k + 4 = 0 ∴ – 4 (3k2 + ...

101 वोट

k2x2 – 2 (k – 1)x + 4 = 0Sol. k2x2 – 2 (k – 1)x + 4 = 0Comparing with ax2 + bx +