find the value of k, if quadratic equation 6x^2 + 5x - K =0 has two real and equal roots
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Answer:
the real and equal zeroes means
b^2-4ac must be zero
b=5
a=6
c= -k
b^2- 4ac = (5)^2- 4.6.(-k)
25+24k =0
24k= -25
k= - 25/24
hope it helps.......
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