find the value of k if system has no solution kx-5 y=2, 6 X + 2 Y = 7
Answers
Answered by
0
hii. .....friend!!
the answer is here,
=> kx-5y=2.
=> 6x+2y=7.
There is no solution. So,
a1/a2 = b1/b2.
=> k/6 =-5/2
=> k =6×(-5)/2
=> -15.
:-)Hope it helps u
the answer is here,
=> kx-5y=2.
=> 6x+2y=7.
There is no solution. So,
a1/a2 = b1/b2.
=> k/6 =-5/2
=> k =6×(-5)/2
=> -15.
:-)Hope it helps u
Answered by
0
Heya dear !!!!
KX - 5 = 2 -------(1)
6X + 2Y = 7 -------(2)
These equations are of the form of A1X + B1Y + C1 = 0 And A2X + B2Y + C2 = 0.
Where,
A1 = K , B1 = -5 and C1 = -2
And,
A2= 6 , B2 = 2 and C2 = -7
It is given that the given equations has no solution.
For no solution we must have;
A1/A2 = B1/B2 not equal C1/C2
K/6 = -5/2 not equal -2/-7
2K = -30
K = -30/2 => -15
:-)..... HOPE IT WILL HELP YOU..... (-:
KX - 5 = 2 -------(1)
6X + 2Y = 7 -------(2)
These equations are of the form of A1X + B1Y + C1 = 0 And A2X + B2Y + C2 = 0.
Where,
A1 = K , B1 = -5 and C1 = -2
And,
A2= 6 , B2 = 2 and C2 = -7
It is given that the given equations has no solution.
For no solution we must have;
A1/A2 = B1/B2 not equal C1/C2
K/6 = -5/2 not equal -2/-7
2K = -30
K = -30/2 => -15
:-)..... HOPE IT WILL HELP YOU..... (-:
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