Question

${x}^{2} - 2 \sqrt{3} x - 9 = 0$
Factorise and find the value of x in either integer or in fraction

Answer 1

hii......friend

the answer is here,

$= > \: {x}^{2} - 2 \sqrt{3} x - 9 = 0$

$= > \: {x}^{2} - 3 \sqrt{3} x + \sqrt{3} x - 9 = 0$

$= > \: x(x - 3 \sqrt{3} ) + \sqrt{3} (x - 3 \sqrt{3} ) = 0$

$= > \: (x - 3 \sqrt{3} )(x + \sqrt{3} ) = 0$

So,

$= > \: x = - \sqrt{3} \: \: and \: \: 3 \sqrt{3}$

:-)Hope it helps u.

Answer 2

Heya dear !!!


( X)² - 2✓3X - 9 = 0



X² -3✓3 X + ✓3 X - 9 = 0



X ( X - 3✓3) + ✓3 ( X - 3✓3) =0



( X - 3✓3) = 0 OR ( X + ✓3) = 0



X = 3✓3 OR X = -✓3.




:-) ....... HOPE IT WILL HELP YOU..... (-: