Hindi, asked by veromicspop, 8 months ago

find the value of K, if $\sqrt[4]{3 \sqrt{ {x}^{2} } } = {x}^{k}$

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Answered by Anonymous

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Answered by BRAINLYADDICTOR

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=> $\sqrt[4]{3 \sqrt{ {x}^{2} } } = {x}^{k}$

$here \\ a = 3. \: b = k \sqrt{3} . \: c = 4 \\ = > b {}^{2} - 4ac = 0 \\ = > (k \sqrt{3) } {}^{2} - 4(3)(4) = 0 \\ = > k {}^{2} 3 - 48 = 0 \\ = > k {}^{2} = 48 \div 3 \\ =>k {}^{2} = 16 \\ =>k = +-4$

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find the value of K, if $\sqrt[4]{3 \sqrt{ {x}^{2} } } = {x}^{k}$