find the value of k if the angle between line kx+y=2 and (2-√3)x-y=1-2√3 is 60 degree.
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Slope of line k.x+y+9=0 is m1= -k.
Slope of line 3.x-y+4=0 is m2= 3.
theta = 45°.
tan (theta) = (m2-m1)/(1+m1.m2).
or, tan45° = (3+k)/(1–3.k).
or, 1 = (3+k)/(1–3k).
or, 3+k = 1–3k.
or, 4.k = -2
or, k = -2/4 = -1/2.