find the value of K if the distance between the points (3,2k) and (4,1) is √10 units
Answers
Answered by
6
1²+(2k-1)²=10
2k-1=±3
k=(2,-1). →2 solutions
2k-1=±3
k=(2,-1). →2 solutions
Answered by
5
Answer:
Step-by-step explanation:
by distance formula
(root over 10)^2=(x1 - x2) + (y1 - y2)
10=(3 - 4) + (2k- 1)
10= -1 +2k -1
10 = -2+2k
12 = 2k
k=6
even if u dont get correct answer the put x1 instead of x2 and x2 instead of x1 and same for y1,y2 in distance formula
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