Physics, asked by 123ambitious, 1 year ago

The least count of a stop watch is 1/5 second the time of 20 oscillation of a pendulum is measured to be 25 seconds the maximum percentage error in the meaaurment of time

Answers

Answered by JinKazama1
149

Final. Answer :Maximum percentage error in time taken., = 0.8%

Steps :

1) Least count ,

\Delta t =\frac{1}{5}=0.2s

Time taken to complete 20 oscillations, T = 25 s

No. of Oscillations , N = 20

Percentage error in measurement of time ,

\frac{\Delta T}{T}*100\% =?

We shall find relative error,

 T = \frac{t}{N}\\ \\=> ln(T) = ln(\frac{t}{N})\\ \\=> ln(T) = ln(t)-ln(N) \\ \\=>\frac{\Delta T}{T}=\frac{\Delta t}{t}+0

We get ,

 T=\frac{t}{N}\\ \\=\frac{\Delta T}{T}=\frac{\Delta t}{t}\\ \\=\frac{\Delta T}{T}*100 \%\\ \\ =\frac{\Delta t}{t}*100 \%\\ \\ = \frac{0.2}{25}*100 = 0.8\%

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Answered by Kinra
60

Answer. Here is the solution to your problem....

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