) find the value of k if the division of Kx³9x²+4x-10
+4x to hy X+3 leaves a reminder - 22
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Correct Question :
find the value of k if the division of Kx³ + 9x² + 4x - 10 by x + 3 leaves a reminder - 22
Solution :
By remainder theorem then +(x) is divide by x + a then its leavesa remainder of f(-a)
f(x) = Kx³ + 9x² + 4x - 10
remainder when f(x) is divide by x + 3 is f(-3)
f(-3) = -22
= K(-3)³ + 9(-3)² + 4(-3) - 10
= -27K + 81 - 12 - 10 = -22
= -27K = -22 + 12 + 10 - 81
= -27K= -81
= K = 3
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