Math, asked by arpitdhaneria, 1 year ago

Find the value of k if the graph of the equation 3x+ky=5 passes through the point (-1,2) . For what value of k will the graph pass through (1,0) ?

Answers

Answered by rational

$3x+ky=5$

Plugin the given point $(-1, 2)$ and solve $k$
$3(-1)+k(2)=5\\-3+2k=5\\2k=8\\k=4$

Second part is bit tricky :
Plugging in the point $(1,0)$ gives
$3(1)+k(0)=5\\3+0=5\\3=5$
which is impossible. so there is no $k$ such that the line $3x+ky=5$ passes through $(1,0)$

arpitdhaneria: Iam not able to solve the second part only

arpitdhaneria: this part i have already solved

rational: Ahh okay, how are you stuck on second part ?

rational: we just need to plugin x=1, y=0 and solve k

rational: wow! okay I see it is tricky... let me update the answer with second part also :)

arpitdhaneria: ok

rational: updated, please see if it makes sense

arpitdhaneria: it is correct or not

rational: Question is fine, it is just that there is no k value which makes the given line pass through given point.

rational: (thats for second part)

Answered by MADHANSCTS

3x+ky = 5
when we substitute (x,y) = (-1,2) in 3x+ky = 5
3(-1)+k(2) = 5
2k=8
k=4

when we substitute (x,y) = (1,0) in 3x+ky = 5
3(1)+k(0) = 5
3 = 5
therefore it is not possible to the line 3x+ky = 5 to pass into the point (1,0)

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