find the value of k if the line 3kx=5+2y pass through: 1) (1, 1)
2) (1, 2)
3) (2, 1)
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Given: The equation 3kx = 5 + 2y
To find: The value of k .
Solution:
- The given points are 1) (1, 1) , 2) (1, 2) , 3) (2, 1)
- Putting (1,1), we get:
3k(1) = 5 + 2(1)
3k = 7
k = 7/3
- Putting (1,2), we get:
3k(1) = 5 + 2(2)
3k = 9
k = 3
- Putting (2,1) , we get:
3k(2) = 5 + 2(1)
6k = 7
k = 7/6
Answer:
So the value of k is 7/3, 3, 7/6 for 1) (1, 1) , 2) (1, 2) , 3) (2, 1) .
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