Question

Find the value of k,if the point(2,3)is equidistant from the points a(k,1)and b(7,k).

Answer 1

Answer:

13

Step-by-step explanation:

let A (k,1), B (7,k) is equidistant from C (2,3)

ie., AC = BC

=> √[(k-2)²+(1-3)²] = √[(7-2)²+(k-3)²]

=> (k-2)²+(-2)² = (5)²+(k-3)²

=> k² - 4k + 4 + 4 = 25 + k² - 6k + 9

=> -4k + 8 = 34 - 6k

=> 6k-4k = 34 - 8

=> 2k = 26

=> k = 13