Question

for what value of k, the equation kx^2 - 6x -2 = 0 has equal roots

Answer 1

On comparing the given equation with { ax² + bx + c = 0 }, we get

a = k
b = - 6
c = - 2






As we know, Discriminant = b² - 4ac
And for equal roots, discriminant = 0


= > ( - 6 )² - 4( - 2k ) = 0


= > 36 + 8k = 0


= > - 36 = 8k


= > - 36 / 8 = k


= > - 9 / 2 = k
$\:$

Answer 2

Hy.....⭐‼

Use formula

D²= b²-4ac

a=k
b=-6
c=-2

Put in formula
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D²=(-6)²-4*k*(-2)

=36+8k

$\sqrt{36} \: = 6$
=6+8k

D=0

8k=0+6

K=6/8

K=3/4

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