Question

Find the value of k if the point (2, 4) is equidistant from the points A (5, k) and B (k, 7).​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Point P(2, 4) is equidistant from the points A(5, K) and B(K, 7). So PA = PB ⇒ PA2 = PB2 ⇒ (5 – 2)2 + (k – 4)2 = (k – 2)2 + (7 – 4)2 ⇒ 9 + K2 + 16 – 8K = K2 + 4 – 4K + 9 ⇒ K2 – 8K + 16 – K2 – 4 + 4K = 0 ⇒ -4K + 12 = 0 ⇒ -4K = -12 ⇒ K = -12/-4 = 3 Hence kk-3 -4