find the value of k if the point A (5,4) B (- 3,k) and C (0,4) are collinear
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93Answer:
Step-by-step explanation:
Given
A(5,4) B(-3,K) C(0,4)
Area of Triangle = 1/2 [X1 (y2-y3)+X2(y3-y1)+X3(y1-y2)]
0=1/2[5(k-4)+(-3)(4-4)+0(4-k)]
0*2=[5K-20+(-3)(0)+0]
=[5K-20+0+0]
= 5K-20
5K= -20
K= -20/5
K= -4
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