Question

Find the value of k, if the points A(2,3), B(4,k), C(6,-3) are collinear.

Answer 1

Since the given points are collinear,
Therefore,
X1(Y2 - Y3) +X2 (Y3 - Y1) +X3 (Y1 - Y2) =0
2(k+3) +4(-3-3) + 6(3-k)=0
2k +6 +4(-6) +18 - 6k=0
2k + 6 - 24 +18 - 6k=0
-4k - 18+18=0
-4k =0
K = 0

Answer 2

Answer:

Step-by-step explanation:

As in the Q these points are collinear then (4,k) will be (4,0). So k = 0