Question

find the value of k if the points A is equal to 2, 3 b is equal to 4, k and c 6 - 3 are collinear

Answer 1

Hi

Here is your answer

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Answer:

                         k  = 0

Step-by-step explanation:

A(2,3) B(4,k) C(6,-3)

Formula - 1/2 [ x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)] = 0

x₁ = 2, x₂ = 4, x₃ = 6          y₁ = 3, y₂ = k, y₃ = - 3

 1/2[ 2(k+3) + 4(-3 - 3) + 6(3 - k) = 0

[ 2k + 6 - 24 + 18 - 6k] = 0 * 2

-4k +24 - 24 = 0

- 4k = 0

Therefore,

k  = 0

Hope it helps U... :)