Find the value of 'K' if the points (K,3),(6,-2)and(-3,4)are collinear
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Step-by-step explanation:
if the points are collinear area of tringle is 0
area of triangle = 1/2 ! k 3 1 !
! 6 -2 1!
! -3 4 1!
(the thing in exclamation marks is determinant)
the above determinant x 1/2 =0
k [ -2-4] - 3 (6+3) + (24-6) =0
-6k -27 + 18 =0
-6k = 9
k = -3/2
hope it helps
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