find the value of k if the polynomial P(x)=kx²+9x³+4x -10 is divided by (x-3)leaves a remainder -22
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The answer according to ur question is 'k' = –267÷9 = –29.67
substitute value of x=3 in quad eqn and solve it
LHS = –22 (REMAINDER GIVEN
I feel u typied the q wrong else my solution is right
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