find the value of k if x+1 is a factor of kx square-x-4
Answers
Answered by
2
(x+1) is a factor of the given polynomial.
» x+1 = 0
» x = -1
Given polynomial,
kx²-x-4 = 0
k(-1)²-(-1)-4 = 0
k(1)+1-4 = 0
k-3 = 0
k = 3
» x+1 = 0
» x = -1
Given polynomial,
kx²-x-4 = 0
k(-1)²-(-1)-4 = 0
k(1)+1-4 = 0
k-3 = 0
k = 3
Similar questions