Question

Find the value of K if x-1
is a factor of
p(x) = 2x² + kx + √2​

Answer 1

Step-by-step explanation:

hey mate!!

x= 1

p(1) = 2 (1)^2 + k(1) + √2=0

=2 + k+√2=0

k= -2-√2

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Answer 2

Answer:

x-1=0

x=1

therefore we need to put the value of x in the equation.

p(1) =2(1) ^2+k(1) +√2

=2+1k+√2

therefore

2+1k+√2=0

k= -2-√2