Question

Find the value of k, if x-1 is a factor of p(x) in each of the following cases :-
$p(x) = 2 {x}^{2} + kx + \sqrt{2}$
​

Answer 1

Answer:

let p(x)=2 X square +kx + 2

g(f)=x minus 2

x minus 2 equal to zero

then X equal to 2

Step-by-step explanation:

now putting the value of P(x)=2×2+k(2)+2

4+2k+2

6+2k

2k=6

k=6/2

k = 3