Question

Find the value of k, if x – 1 is a factor of p(x) in each of the following

cases:

(i) p(x) = x^2+ x + k
(ii) p(x) = 2x2 + kx + √2

Answer 1

f(1)=1^2+1+k
0=2+k
k=-2

(2)..p(1)=2×1^2+k×1+√2
0=2+k+√2
k=-2-√2

Answer 2

Answer:

x - 1 = 0

x = 1

p(x) =2x^{2}2x

2

+kx +\sqrt{2}

2

p(x) = 2(1)^{2}2(1)

2

+ k(1) + \sqrt{2}

2

= 2 + k + \sqrt{2}

2

2+ k +\sqrt{2}

2

= 0

k = -2 -\sqrt{2}

2

hope it help uh dear!! ✌