find the value of k if x+1 is a factor of p(x)=kx^2-x-4
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Answered by
1
Put x=-1 as the factor is x+1
So p(1)=k×(-1)^2+1-4=0
So p(1)=k×(-1)^2+1-4=0
Answered by
2
apply reminder theorem
=×-1=0
=×=1
according to remainder theorem p[1] =0
we get plug ×=1 we get
= k (1)² + 1+1=0
=k +1+1 = 0
=k+2=0
k= -2
=×-1=0
=×=1
according to remainder theorem p[1] =0
we get plug ×=1 we get
= k (1)² + 1+1=0
=k +1+1 = 0
=k+2=0
k= -2
joannasuzanne77:
x+1?
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