Question

let k be the HCF of 609 and 957 determine x and y such that k= 609x+957y and establish that x and y are not unique.

Answer 1

i hope it helps...............

Answer 2

Heya mate here is ur ans:-

$k = 609x + 957y \\ 957 = 609 \times 1 + 348 \\ 609 - 348 \times 1 + 87 \\ 261 = 87 \times 3 + 0 \\ \\ \\ \\ now \\ \\ 87 = 348 - 261 \times 1 \\ 87 = 348 - (609 - 348 \times 1) \times 1 \\ 87 = 348 - (609 - (957 - 609 \times 1) \times 1) \\ 87 = - 957 - 609 \times 1(609 - 957 + 609) \\ 87 = 957 \times 2 + 609 \times 3 \\ \\ x = 3 \\ y = 2$

Hope its help!!!✌✌✌

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