Question

find the value of k if x-1 is a factor of p(x)=kx2+2X+1

Answer 1

Answer:

Step-by-step explanation:

X-1 is factor so

X-1=0

X=1

p(1)=k(1)+2(1)+1=0

= k +2+1=0

k+3=0

k=-3

Answer 2

Answer:

$\large\boxed{\star\:\:\:\:\:\:k=(-3)\:\:\:\:\:\:\star}$

Step-by-step explanation:

✮Given:-

  (x-1) is a Factor of Quadratic Equation kx²+2x+1.

✮To Find:-

The Value of k.

✮Solution:-

g(x)=x-1=0

x-1=0

→x=1

p(x)=kx²+2x+1=0

Putting x=1 in the Equation:-

⇒p(1)=[k×(1)²]+[2×(1)]+1=0

⇒(k×1)+(2×1)+1=0

⇒k+2+1=0

⇒k+3=0

$\implies\boxed{k=(-3)}$