Question

Find the value of k if x-1 is a factor Of P(x)
p(x) = x square + x + K​

Answer 1

Answer:

According to the Question

p(x) = kx² - 3x + k

If (x - 1) is a factor of p(x)

Therefore

x - 1 = 0

x = 1

Substitute the value of x in Equation

⇒ k(1)² - 3 × 1 + k = 0

⇒ 2k - 3 = 0

⇒ 2k = 3

⇒ k = \bf\huge\frac{3}{2}23

Answer 2

Answer:

hey mate here is ur answer

the value of k

=

first of all we have to find the value of x

x-1=0

,x=1

now we will find the value of k

x^2+x+k=0

1×1+1+k=0

1+1+k=0

2+k=0

k=0-2

k=-2

hope this is helpful to u

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