Question

Find the value of k, if x-1 is a factor of p(x) = x 2 +x+k.

Answer 1

Step-by-step explanation:

$if \: (x - 1) \\ x - 1 = 0 \\ x = 1$

Insert the value of x in the equation.

$p(x) = {x}^{2} + x + k \\ p(1) = {(1)}^{2} + 1 + k \\ = 1 + 1 + k \\ = 2 + k \\ ( - 2) = k$

The value of k is (-2)