find the value of k if (x+1) is a factor of x cube+3x square +6x+k
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Answer: x^3 + 3x^2 + 6x + k
p(-1)= (-1)^3+3(-1)^2+6(-1)+k
= -1+3-6+k
= 2-6+k
0 = -4 + k
0 + 4 = k
∴k=4
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