Math, asked by msavaf, 8 months ago

find the value of k if (x+1) is a factor of x cube+3x square +6x+k​

Answers

Answered by chrissy777
0

Answer: x^3 + 3x^2 + 6x + k

p(-1)= (-1)^3+3(-1)^2+6(-1)+k

     = -1+3-6+k

     = 2-6+k

 0 = -4 + k

  0 + 4 = k

   ∴k=4

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Answered by utsav96
2
Pls mark as brainliest answer
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