Question

find the value of k if x^2 +5x+k is divisaible by(x+2) exactly​

Answer 1

Answer:

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Answer 2

Given that,

when

(x−

1)

is factor of

x 2

+

5x−

2k

.

(1)

2

+

5×

1−

2k=

0

1+

5−

2k=

0

6−

2k=

0

2k= 6

⇒

k=

3

Putting

x=

1

. the remainder will be equal to zero.