find the value of k if (x-2) is a factor of p (x)=3x^3+4x^2-20x+k+2
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Answer :
k = -2
Step-by-step explanation :
⇒ Cubic Polynomial :
- It is a polynomial of degree 3.
- General form :
ax³ + bx² + cx + d
- Relationship between zeroes and coefficients :
☆ Sum of zeroes = -b/a
☆ Sum of the product of zeroes taken two at a time = c/a
☆ Product of zeroes = -d/a
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Given polynomial,
p(x) = 3x³ + 4x² - 20x + k + 2
=> (x - 2) is a factor
x - 2 = 0
x = +2
Since (x - 2) is a factor,
substitute x = + 2 in the given polynomial, the result is zero.
p(2) = 0
3(2)³ + 4(2)² - 20(2) + k + 2 = 0
3(8) + 4(4) - 40 + k + 2 = 0
24 + 16 - 40 + k + 2 = 0
40 - 40 + k + 2 = 0
k + 2 = 0
k = -2
∴ The value of k is -2
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