Question

find the value of k if (x+2) is a factor of p(x)=kx2-√2x+1​

Answer 1

Hey

p(x)=kx^2-√2x+1

g(x)=x+2=>x=-2

Thus,

p(x)=p(-2)

=>p(-2)=k(-2)^2-√2(-2)+2

=>4k+2√2+2=0

=>2k+√2+1=0

=>2k=-(√2+1)

=>k= -(√2-1)/2

Answer 2

Step-by-step explanation:

Since g(x)=x+2 is a factor of p(x)= kx²-√2x+1

=> x+2=0

=>x=(-2) ---------------------(1)

                Substitute (1) in p(x)

k(-2)²-√2(-2)+1=0

k(4)+√4+1=0

4k+2+1=0

4k+3=0

4k=(-3)

k=(-3/4)

HOPE IT HELPS.....