Find the value of k if x-2 is a factor of the polynomial kx square - root 2x + 1
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Answered by
10
Hey there !
Thanks for the question !
Here's the answer !
Given that, x - 2 is a factor
=> x = 2
Equation = kx² - √2 x + 1 = 0
Substituting x = 2 we get,
=> k ( 2 )² - √2 ( 2 ) + 1 = 0
=> 4k - 2√2 + 1 = 0
=> 4k = 2√2 - 1
=> k = ( 2√2 - 1 ) / 4
Hope my answer helped !
Answered by
0
hope this answer helps u :)
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