Question

Find the value of k if x-2 is a factor of the polynomial p(x) = kx2-√2 x+ 1
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Answer 1

Answer:

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Step-by-step explanation:

ANSWER ::

The zero of the polynomial x - 2 is given by

x - 2= 0

= 0So x = 2

Let f(x) = kx² - √2x + 1

Now by the Remainder Theorem the required Remainder is

Now by the Remainder Theorem the required Remainder is f(2) = k×2² - √2× 2 + 1 = 4k - 2√2 + 1

So

4k - 2√2 + 1 = 0

k = ( 2√2 - 1) /4

Answer 2

Answer:

HERE THE ANSWER

Step-by-step explanation:

p(x)=kx^2- 2+1

if (x-2) is a factor of p(x)

then p(2)=0

 k*(2)^2-root 2 +1=0

4 k- root 2+1=0

4k= root2-1

k= root2 -1/4

hope you got the answer...........