Math, asked by Hemadolli, 11 months ago

Find the value of 'K' if (x-3) is a factor

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Answered by BrainlyPopularman

Answer:

GIVEN EQUATION :-

K² X³ - KX² + 3 KX - K =0 , have a factor (x - 3) .

SO , X = 3 SATISFY THE EQUATION

=》 K²(3)³ - K (3)² + 9K -K = 0

=》 27 K² - 9K + 8K = 0

=》 27 K² - K = 0

=》 K = 0 , K = 1/27

Answered by Anonymous

$\huge \red { \bigstar{ \underline{ÀNSWER}}}$

$<body bgcolor ="Greee"> <font color = black>$

if (x-3) is a factor of

${k}^{2} {x}^{3} - k {x}^{2} + 3kx - k$

then,

(x-3)=0

x=3

${k}^{2} \times {3}^{3} - k \times {3}^{2} + 3k \times 3 - k \\ \\ 27 {k}^{2} - 9k + 9k - k \\ \\ 27 {k}^{2} - k = 0 \\ \\ \frac{ - b + - \sqrt{ {b}^{2} -4ac } }{2a} \\ \\ a = 27 \\ b = - 1 \\ \frac{1 + - \sqrt{1 - 4 \times 27 \times 0} }{54} \\ \\ \frac{1}{54} \\$

$\huge \red { \bigstar{ \underline{k = \frac{1}{54} }}}$

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then,

(x-3)=0

x=3

Find the value of 'K' if (x-3) is a factor