Find the value of k if x-3 is a factor of k²x³ - kx² + 3kx - k.
Answers
Let, f (x) = k²x³ - kx² + 3kx - k
By factor theorem, If (x - 3) is a factor of f(x) then f (3) = 0 :
⇒ k²(3)³ - k(3)² + 3k(3) - k = 0
⇒ k² × 27 - k × 9 + 9k - k = 0
⇒ 27k² – 9k + 9k – k = 0
⇒ 27k² – k = 0
⇒k (27k – 1) = 0
⇒k = 0 or (27k – 1) = 0
k = 0 or k = 1/27
Hence, (x - 3) is a factor of f (x) when k = 0 or k = 1/27.
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- g(x)=>x-3=0
=>x=3
Now,
f(x)=>k²x³ - kx² + 3kx - k=0
putting the value of x
=> k²(3)³ - k(3)² + 3k(3) - k = 0
=> k² × 27 - k × 9 + 9k - k = 0
=> 27k² – 9k + 9k – k = 0
=> 27k² – k = 0
=>k (27k – 1) = 0
k = 0 or k = 1/27
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