Question

find the value of k if (x-7) is a factor of kx2-√2x+1​

Answer 1

Given, (x - 7) is factor of the above equation

$p(x) = k {x}^{2} - \sqrt{2} x + 1$

then, x - 7 = 0

=> x = 7

Putting, x = 7 in given equation, we get

$p(7) = > k ({7})^{2} - \sqrt{2} (7) + 1 = 0$

$=> 49k - 7 \sqrt{2} + 1 = 0$

$=> 49k = 7 \sqrt{2} - 1$

$=> k = \frac{7 \sqrt{2} - 1}{49}$

Hope its helpful for you.

Answer 2

Answer:

same answer to me

hope I help you