Find the value of k, if x+k is the factor of polynomial : x^4-k^2x^2+3x-6k
Answers
Answered by
126
Hey dear!
Here is yr answer.....
x+k = 0
x = -k
x^4-k^2x^2+3x-6k = 0
(-k)^4-k^2(-k)^2+3(-k) -6(-k) = 0
k^4-k^4-3k+6k = 0
3k = 0
k = 0/3
k = 0
Hope it hlpz....
Here is yr answer.....
x+k = 0
x = -k
x^4-k^2x^2+3x-6k = 0
(-k)^4-k^2(-k)^2+3(-k) -6(-k) = 0
k^4-k^4-3k+6k = 0
3k = 0
k = 0/3
k = 0
Hope it hlpz....
Answered by
64
Heya !!!
Given that ( X +K ) is a factor of the given polynomial.
(X +K) = 0
X = -k
P(X) = X⁴ - K²X² +3X - 6K
P(-K ) = (-K)⁴ - K² (-K)² + 3 × - K -6K = 0
=> K⁴ -K⁴ - 3K -6K = 0
=> -9K = 0
=> K = 0/-9
=> K = 0
HOPE IT WILL HELP YOU...... :-)
Given that ( X +K ) is a factor of the given polynomial.
(X +K) = 0
X = -k
P(X) = X⁴ - K²X² +3X - 6K
P(-K ) = (-K)⁴ - K² (-K)² + 3 × - K -6K = 0
=> K⁴ -K⁴ - 3K -6K = 0
=> -9K = 0
=> K = 0/-9
=> K = 0
HOPE IT WILL HELP YOU...... :-)
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