Question

find the value of k if x minus 2 is a factor of polynomial P bracket x is equal to x cube minus 6 X square + 5 x + k

Answer 1

heya!!

here given: x-2 is a factor
and p(x)=x^3-6x^2+5x+k

=>x-2=0
=>x=2

put the value of x in p(x).

=> (2)^3-6(2)^2+5(2)+k=0

=>8-24+10+k=0

=>k=24-18

=>k=6

hope this helps you ☺

Answer 2

Answer:

The value of k is 6

Step-by-step explanation:

We have to find the value of k if (x-2) is the factor of the polynomial

$P(x)=x^3-6x^2+5x+k$

By using remainder theorem, as (x-2) is the factor of given polynomial then the remainder must be 0

$P(2)=0$

⇒ $2^3-6(2)^2+5(2)+k=0$

$8-24+10+k=0$

$k=14-8=6$

Hence, the value of k is 6