Question

find the value of k if x2-6x+k has real and distict roots

Answer 1

Answer:

let a=2 b=6 and c=1

For real and distinct roots,

D = 0

b²-4ac. =0

=6²-4*2*k =0

=36-8k =0

= -8k =-36

= k =4.5

therefore the value of k is 4.5

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