Question

Find the value of k if x2 + kx + 6 = (x
+2) (x + 3) for all k. *​

Answer 1

Step-by-step explanation:

x2+kx+6=(x+2)(x+3)

x2+kx+6=x(x+3)+2(x+3)

x2+kx+6=x2+3x+2x+6

x2+kx+6=x2+5x+6

here x2 and 6 get cancelled and we get

kx=5x

where k becomes

k=5x÷x

where x get cancelled and we get

k= 5