Question

Find the value of K if y-1 is a factor of P(y)=Ky2-3y+K.

Answer 1

Answer:

k=3/2

Step-by-step explanation:

y-1=0

y=1

P(y)=ky^2-3y+k

P(1)=k(1)^2-3(1)+k

k-3+k=0

k-3=-k

k=-k+3

k+k=3

2k=3

k=3/2

MARK ME AS BRAINLIEST PLEASE.