Question

if x=2a²+3b²-5ab, y=b²-3a²+7ab and z= 6a²-b²+ab find x+y-z​

Answer 1

Your answer is ....

$- 7a ^{2} + 3b ^{2} + 3ab$

You can either find the answer by using identities or by normal method of addition and subtraction of algebraic expressions.

Hope this helps you✌️