Question

Find the value of k if y+3 is a factor of 3ysquare + ky +6

Answer 1

Answer:

Hey mate

Y+3=0

Y=-3

Now,

=>3y^+ky+6=0

=>3×(-3)^-3k+6=0

=>27-3k+6=0

=>3k=33

=>k=11

Hence, the value of k is 11.

Hope it will be helpful to you

Thanks ♥️✌️

Answer 2

Step-by-step explanation:

y+3=0

y=-3

3y2+ky+6

3(-3)2+k(-3)+6

27-3k+6

33-3k=0

-3k=-33

k=-33÷(-3)

k=11

hence proved

Hope it is helpful

tysm

lots of love