find the value of k if y cube + K Y + 2 k - 2 exactly divisible by y + 1
Answers
Answered by
16
Let f (x)=y^3+ky+2k-2
y+1=0
=)y=-1
Now,
since , polynomial f (x) is divisible by (y+1)
then,
=)f (-1)=0
=) (-1)^3+k (-1)+2 (-1)-2=0
=) -1-k-2-2=0
=) -5-k=0
Hence, k=-5
Hope it helps u.
y+1=0
=)y=-1
Now,
since , polynomial f (x) is divisible by (y+1)
then,
=)f (-1)=0
=) (-1)^3+k (-1)+2 (-1)-2=0
=) -1-k-2-2=0
=) -5-k=0
Hence, k=-5
Hope it helps u.
kirti55:
no please try again
check ur ans
correct ans is k=3
how?
-5 is correct ans
u can check in equation by putting value of k in LHS..
you got LHS=RHS...belief in method or concept not ans.
Answered by
0
Step-by-step explanation:
this is your answer bro please give me thanxs
Attachments:
Similar questions