Question

Find the value of k in each of the following:
(2/3)³×(2/3)⁶=(4/9)²k-3
​

Answer 1

Answer:

76h4

Step-by-step explanation:

Answer 2

Answer:

K=15/4

Step-by-step explanation:

(2/3)³×(2/3)⁶=(4/9)²k-³

the bases are same and the powers are different so we have add the powers.

Then we split the numbers 4/9 and keep the power as it is.

(2/3)⁹=(2×2/3×3)²k-³

(2/3)⁹=(2/3)²k-³ (2/3)²k-³

Now,in the RHS the bases are same and power are also same.so,we will add the power.

(2/3)⁹=(2/3)²k-³+²k-³

(2/3)⁹=(2/3)⁴k-⁶

Therefore,

9=4k-6

4k=6+9

4k=15

k=15/4

I hope the answer is clear to you.

Thank you