Question

Find the value of K, in quadratic equation 9x^2-kx+16=0 , if root are equal

Answer 1

Answer:

K = 24

Step-by-step explanation:

b^2 - 4ac = 0

K^2 - 576

K = 24

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Answer 2

Answer:

$9x {}^{2} - kx + 16 \\ if \: root \: are \: equal \: then \: b {}^{2} - 4ac = 0 \\ a = 9 \: \: \: b = - k \: \: c = 16 \\ -k {}^{2} - 4(9)(16) = 0 \\ - k {}^{2} = 576 \ \\ - k = \sqrt{576 } \\ - k = 24 \\ k = - 24$